In the given figure, a circle touches all the four sides of a
quadrilateral ABCD whose sides are AB = 6 cm, BC = 8 cm,
AP = 2.5 cm and CD = 7 cm. Find the length of side AD.
Answers
Answer:
Given : A circle inscribed in a quadrilateral ABCD,AB=6cm,BC=7cm,CD=4cm.
To find : AD
Proof : Let the circle touch the sides AB,BC,CD,DA, at P,Q,R and S, respectively.
AP=AS
BP=BQ
DR=DS
CR=CQ {Lengths of two tangents drawn from an external point of circle, are equal}
Adding all these, we get
(AP+BP)+(CR+RD)=(BQ+QC)+(DS+SA)
AB+CD=BC+DA
⇒6+4=7+AD
⇒AD=10−7=3cm.
pehla wale question ka answer likha kya
Answer:
- Given : A circle inscribed in a quadrilateral ABCD,AB=6cm,BC=7cm,CD=4cm.
To find : AD
Proof : Let the circle touch the sides AB,BC,CD,DA, at P,Q,R and S, respectively.
AP=AS
BP=BQ
DR=DS
CR=CQ {Lengths of two tangents drawn from an external point of circle, are equal}
Adding all these, we get
(AP+BP)+(CR+RD)=(BQ+QC)+(DS+SA)
AB+CD=BC+DA
⇒6+4=7+AD
⇒AD=10−7=3cm.