in the given figure a d parallel CD parallel to EF find the value of x
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/_ABC = /_BCD = 70° [ Alternate angles]
/_CEF + /_ECD = 180°
130° + /_ECD = 180
/_ECD = 180-130 = 50°
/_BCE = /_BCD - /_ECD
/_BCE = 70-50
/_BCE = 20°
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Answered by
1
/_ABC = /_BCD = 70° [alternate angles]
/_CEF + /_ECD = 180
130 + /_ECD = 180
/_ECD = 180 -130 = 50°
Now
/_BCD = 70
50 + x = 70
x = 70 - 50 = 20°
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