Question

In the given figure,
A) Prove that triangle ABC is similar to triangle ABP is similar to triangle ACP.
B) AP^2 = BP×PC

Please help me. ​

Answer 1

Step-by-step explanation:

ABC and △DBC are two isosceles triangles on the same base BC and vertices A and D are on the same side of BC. If AD is extended to intersect BC at P, show that

(i) △ABD≅△ACD

(ii) △ABP≅△ACP

(iii) AP bisects ∠A as well as △D.

(iv) AP is the perpendicular bisector of BC.

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Answer 2

Answer:

i hope it helps u

Step-by-step explanation:

In the given figure,

A) Prove that triangle ABC is similar to triangle ABP is similar to triangle ACP.

B) AP^2 = BP×PC

Please help me.