Question

In the given figure, a ray of light falls obliquely on a glass slab of refractive inde √3 and thickness 5-√3 cm as shown. The lateral displacement suffered by light ray is​

Answer 1

Answer:

Concept : There is a direct formula for this kind of questions which is lateral displacement

x=(

cosr

t

)sin(i−r)

Here, t is thickness of slab

i is angle of incidence

r is angle of refraction.

Solution: Since, xαt

Hence the slab having more thickness will have maximum lateral displacement and vice versa.

So, slab 3 will have maximum lateral displacement whereas slab 1 will have minimum lateral displacement.

Answer 2

Explanation:

Concept : There is a direct formula for this kind of questions which is lateral displacement

x=(

cosr

t

)sin(i−r)

Here, t is thickness of slab

i is angle of incidence

r is angle of refraction.

Solution: Since, xαt

Hence the slab having more thickness will have maximum lateral displacement and vice versa.

So, slab 3 will have maximum lateral displacement whereas slab 1 will have minimum lateral displacement.