Question

In the given figure a square is inscribed in a circle of diameter and another square is circumscribing the circle. Is the area of the outer square is four times the area of the inner square? give reason
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Answer 1

Answer:

Let the side of the smaller square is a units and that of bigger square is b units.

Diameter of circle =d

So, diagonal of square EFGH=d

Then, by Pythagoras theorem,

a

2

+a

2

=d

2

⇒2a

2

=d

2

⇒a

2

=

2

d

2

∴ Area of smaller square =a

2

=

2

d

2

Side of outer square =b= Diameter of circle

∴ Area of larger square =b

2

=d

2

=> Area of outer square =2 Area of smaller square

So, the given statement is false

Step-by-step explanation:

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