Question

In the given figure, a square OABC is inscribed in a quadrant OPBQ. If OA = 20 cm, find the area of the shaded region. [Use π = 3.14]

Answer 1

HERE IS THE SOLUTION FOR YOUR QUESTION;

◆There is the image of your's question figure◆

Here is the SOLUTION;

In ΔOAB,

OB2 = OA2 + AB2

= (20)2 + (20)2

Radius (r) of circle

Area of quadrant OPBQ

Area of OABC = (Side)2 = (20)2 = 400 cm2

Area of shaded region = Area of quadrant OPBQ − Area of OABC

= (628 − 400) cm2

= 228 cm2

Answer 2

Answer:

228 cm²

Step-by-step explanation:

area of the square =20*20=400 cm²

area of the quadrant =1/4*3.14*20*20*2

                                    =3.14*200

                                    =628cm²

required area =628-400=228cm²