Question

In the given figure AA' and BB'are two common tangent of two circles show that these tangent are the equal

Answer 1

Answer:

construction: produce AA'and BB'to meet at P.

to prove:AA'=BB'

proof:PA=pB

PA'=PB'

tangent to a circle from an external point

PA-PA'=PB-PB'

AA'=BB'

hence proved