Question

In the given figure, AABC is an equilateral triangle whose side BC has been produced in both the
directions to D and E respectively. Prove that ACD =ABE
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Answer 1

Answer:

AC=AB,BE=CD,AD=AE

Step-by-step explanation:

HOPE THIS IS HELPFUL

Answer 2

Step-by-step explanation:

If we extend BC on both ends, then the angles would be,

∠ACD=180−C

∠ABF=180−B

Sum of the 2 exterior angles=∠ACD+∠ABF

=(180−C)+(180−B)

=360−(B+C)

=360−(180−A)=180+A

∠A is always positive.

∴ sum of the angles is greater than 180°.