Question

in the given figure ab = 30 metre, bc = 25 metre and cd =5 m , find the angle theta
(ii) bc=20 m, CD = 4.5 cm and angle theta = 60 degree find the length of AB
(iii) AB = 40m ,CD =8m and angle theta = 30 degree find the length of bc

Answer 1

Step-by-step explanation:

in fig. AB=30M SO AE= 25m

DE=25m

we know that

tantheta=perpendicular/base

=25/25m

=1

tan theta=1

But we know that tan 45°=1

so theta is 45

ii-

giving that<D=60°and DE=20m

DC=4.6m

tan 60°=AE/20

√3 =AE/20

20√3. =AE

SOthe lenth of AB=20√3+4.5

=39.1410162

iii- given AB=40. SO AE=32

THETA=30°

we know that

tan theta=perpendicular/base

tan30° =32/DE

1/√3=32/DE

32√3= DE

55.4256258=DE

DE=BC SO BC=55.4256258

Answer 2

This is correct for sure ✌