Question

In the given figure, AB = 8cm, BC = 3cm and BE is parallel to CD.

(i) FIND—
a) BE/CD ,
b) area of ∆ABC/area of quadrilateral BCDE

(ii) What is the special name given to the quadrilateral BCDE?.


answer me fast please....​

Answer 1

Answer:

(i) a) BE/CD = 8/11

b) area of ∆ABE/area of quadrilateral BCDE

= 64/57

(ii) TRAPEZIUM

NOTE: my answer is absolutely correct!

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