In the given figure, AB = 8cm, BC = 3cm and BE is parallel to CD.
(i) FIND—
a) BE/CD ,
b) area of ∆ABC/area of quadrilateral BCDE
(ii) What is the special name given to the quadrilateral BCDE?.
answer me fast please....
Attachments:
Answers
Answered by
2
Answer:
(i) a) BE/CD = 8/11
b) area of ∆ABE/area of quadrilateral BCDE
= 64/57
(ii) TRAPEZIUM
NOTE: my answer is absolutely correct!
check my attachment for detailed explanation
Attachments:
Similar questions