Question

In the given figure, AB =9 cm, BC= 12 cm and
AC=15 cm.
BP is perpendicular to AC.

Find BP and AP.​

Answer 1

$\bold{\boxed{\huge{\boxed{\orange{\small{\boxed{\huge{\red{\bold{\:Answer}}}}}}}}}}$

in Rt∆ when BP is Perpendicular To AC ,

we have ,

$\large\red{\boxed{\sf BP²=AP*PC}}$

-------------(1)

$\Large\bold{\boxed{\boxed{</strong><strong>AB</strong><strong>\</strong><strong>:</strong><strong>²\:=\:AP\:×\:</strong><strong>A</strong><strong>C}}}$

-------------(2)

using (2) we get,

9² = AP*15

AP = 81/15 (Ans)

PC = 15-(81/15) = 144/15

putting this value in (1) we get,

BP² = (81/15)*(144/15)

BP² = (81*144)/(15)²

BP = 9*12/15 = (36/5) (Ans)

Answer 2

Answer:

In the given figure, AB =9 cm, BC= 12 cm and

AC=15 cm.

BP is perpendicular to AC.

Find BP and AP.

36/5