Question

In the given figure, AB =9 cm, BC= 12 cm and
AC=15 cm.
BP is perpendicular to AC.
measure of angle abc prove the triangle apb is similar to triangle abc
Find BP and AP.​

Answer 1

Answer:

in Rt∆ when BP is Perpendicular To AC ,

we have ,

\large\red{\boxed{\sf BP²=AP*PC}}

BP²=AP∗PC

-------------(1)

-------------(2)

using (2) we get,

9² = AP*15

AP = 81/15 (Ans)

PC = 15-(81/15) = 144/15

putting this value in (1) we get,

BP² = (81/15)*(144/15)

BP² = (81*144)/(15)²

BP = 9*12/15 = (36/5) (Ans