Question

in the given figure ab=9cm bc=12cm and ac is15 cm bp is perpendicular to ac find measure of angle abc prove that triangla apb is similarly to triangle abc find bp and ap​

Answer 1

$\huge\star\underline\mathfrak\red{Answer:-}$

in Rt∆ when BP is Perpendicular To AC ,

\large\red{\boxed{\sf BP²=AP*PC}}

-------------(2)

using (2) we get,

9² = AP*15

AP = 81/15(Ans)

PC = 15-(81/15) = 144/15

putting this value in (1) we get,

BP² = (81/15)*(144/15)

BP² = (81*144)/(15)²

BP = 9*12/15 = (36/5) (Ans)

Answer 2

$\huge\underbrace\mathfrak \red{ANSWER }$

in Rt∆ when BP is Perpendicular To AC ,

\large\red{\boxed{\sf BP²=AP*PC}}-------(2)

using (2) we get,

9² = AP*15

AP = 81/15(Ans)

PC = 15-(81/15) = 144/15

putting this value in (1) we get,

BP² = (81/15)*(144/15)

BP² = (81*144)/(15)²

BP = 9*12/15 = (36/5) (Ans)

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