Question

In the given figure, AB = AC ∠ACM = 125
0
. ∠PAB = ?

Answer 1

Solution :-

in ∆ABC,

→ AB = AC

So,

→ ∠ABC = ∠ACB (Angle opposite to equal sides are equal.)

Now,

→ ∠ACM + ∠ACB = 180° (Linear pair.)

→ 125° + ∠ACB = 180°

→ ∠ACB = 180° - 125°

→ ∠ACB = 55°

So,

→ ∠ABC = ∠ACB = 55°

Now,

→ ∠ABC + ∠ACB + ∠BAC = 180° (angle sum property.)

→ 55° + 55° + ∠x = 180°

→ ∠x = 180° - 110°

→ ∠x = 70° (Ans.)