Question

In the given figure, AB=AC and AD=AE. Using Euclid's axiom, prove that BE = DC .


Plzz give appropriate and stepwise answer, 4 marks question Plzz help

Answer 1

be is equal to dc

because ab is equal to ac and ad is equal to ae equal sides are equidistance

Answer 2

Answer:

Step-by-step explanation:

Given AB=AC and AD=AET

Therefore, BD=CE

Draw a line between the BC

Now consider the ΔABC the two side AB=AC so it is a iso-scale triangle

therefore, ∠ABC and ∠ACB are equal.

therefore, ∠DBC=∠ECB

Now in ΔBCD and ΔBCE

BC is common side

BD=CE (proven)

∠DBC=∠ECB

As per the side-side-angle formula

$\Delta{BCD}\cong\Delta{BCE}$

Therefore it is proved

DE=BE