in the given figure ab=ac and angle ACD is 105 degree find angle BAC
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Answer:
Correct option is
C
70
∘
In traingle ABC
AB=AC, hence, ∠ABC=∠BCA
Given, ∠BAC=40
∠ABC+∠BCA+∠BAC=180
∠ABC=∠BCA=
2
180−40
=70
therefore, ∠BCA=70
∘
Now, ∠ACD+∠ACB=180
∠ACD=110
In ΔACD,
∠ACD+∠DAC+∠ADC=180
∠DAC+∠ADC=70
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