In the given figure, AB = AC and B – C – D. Prove that : AD > AB.
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Step-by-step explanation:
Given :– AB = AC,
To prove :– AD > AB
Proof :– We know that the angles oppositeto equal sides are equal.
∴ AC = AB ⇒ ∠ACB = ∠ABC. -----(i)
In ∆ACD , the side DC has been produced to B.
∴ ∠ACB > ∠ADC [ext.∠ is greater than
int. opp. ∠s]
⇒∠ABC > ∠ADC [using (i)]
⇒∠ABD > ∠ADB [∵ ∠ABC = ∠ABD and
∠ADC = ∠ADB]
⇒AD > AB
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