Question

In the given figure, AB = AC and BD = DC. Prove that
(a) triangle ABC is congruent to triangle ACD.
(b) angle ADB = angle ADC = 90°.
(c) angle B = angle C.
(d) Angle BAD = Angle CAD.​

Answer 1

Answer:

(a) AB=AC (given)

BC=DC (given)

AD=AD (common)

therefore,∆ ABD is congruent to ∆ ACD ( By S.S.S rule)

(b) angle adb =angle adc ( by c.p.c.t)

angle adb + angle adc = 180° ( as BC is a straight line )

therefore, angle adb = angle adc = 90°

(c) angle b = angle c ( by c.p.c.t )

(d) angle bad = angle cad ( by c.p.c.t )

Step-by-step explanation:

PLZ MARK ME AS BRAINLIEST