Question

in the given figure, AB =AC and BE =CD. prove that AD =AE​

Answer 1

In ∆ABD and ∆AEC

BE = DC (given) …(i)

Subtracting DE from both side of (i), we get

BE – DE = DC – DE

BD = EC

AB = AC (given)

∠B = ∠C (angle opposite to equal sides are equal)

= ∆ABD ≅ ∆AEC

AD = AE ........ (by c.p.c.t.)

Answer 2

Answer:

Explanation:

In ∆ABD and ∆AEC

BE = DC (given) …

(i) Subtracting DE from both side of (i), we get

BE – DE = DC – DE

=> BD = EC

AB = AC (given)

=> ∠B = ∠C

(angle opposite to equal sides are equal)

=> ∆ABD ≅ ∆AEC

=> AD = AE (by c.p.c.t)