Question

In the given figure, AB =AC and DB = DC. Prove that ∠ABD=∠ACD

Answer 1

Join A to D

In triangle ABD and triangle ACD

AB=AC (given)

DB=DC (given)

AD=AD (common)

By SSS

triangle ABD is congruent to triangle ACD

angle ABD=angle ACD (By CPCT)





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Answer 2

Answer.


In ∆ABC

D is a point on side BC ,

Join A and D


GIVEN =>


AB=AC

BD=CD


PROVE=>


angle. ABD=angle ACD


SOLUTION=>

In ∆ ABD and ∆ ACD

AB = AC

BD= CD

AD =AD. ( common)

so ∆ ABC =_ { ~} ∆ ACD

so ∆ ABC cogurant to ∆ ACD. by (sss)


by cpct

angle ABD= angle ACD