Question

In the given figure
AB=AC and LACD = 105°
find LBAC.

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Answer 1

Answer:

Step-by-step explanation:

angle bcd is a straight angle so, 180-105= 75*

so acb= 75*

since ab=ac

angle BAC is also equal to angle ACB

i.e., BAC=ACB= 75*

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Answer 2

Answer:

given : AB=BC, ACD=105°

to find: BAC

proof: BCD is a straight line so angle is 180°

BCA+ACD=180°

BCA=75°

AB=BC, so ABC = BCA=75°

in triangle sun of all angle is egual to 180°

so, ABC+angle BCA+BAC=180°

BAC=180°-150°

BAC=30°

hence proved

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