Question

In the given figure AB =AC AP=AQ Prove that
CAQ= BAP
(1) ABQC = ACPB

Answer 1

Step-by-step explanation:

In △APC and △AQB

AB=AC and AP=AQ

From the given figure, ∠A=∠A [common in both the triangles

By using corresponding parts of congruent triangles concept we have

∠APC=∠AQB