Question

In the given figure, AB = AC, BD = EC. Prove that ABE = ACD and AD = AE.​

Answer 1

Answer:

Step-by-step explanation:

In triangles ABE and ACD :

given  AB=AC

so, angle ABE=angle ACD (isosceles property)

given  BD=EC

BD+DE=EC+DE (when equals are added to equals the wholes are equals)

so, BE=EC

ABE~ACD (SAS Congruence)

AD=AE (C.P.C.T)