Question

In the given figure AB=AC.prove that BD =BC. Don't ignore this question please give me answer please...

Answer 1

Answer:GIVEN -AB=AC

T.P-BC=BD

PROOF- IN ABD ,

Angle ADB=180- (40 + 30)=110..........(ASP)

Angle BDC=180-110=70

LET ANGLE DBC=X

ANGLE ABC=ACB=BCD...........(Angles opp. To equal sides )

So

Angle ACB=ABC=30+X

IN TRIANGLE BDC

ANGLE DBC+BCD+CDB=180.....ASP

X+(30+X)+70=180

2X+100=180

2X=80

X=40

Now

ANGLE BCD=30+X=30+40=70

ANGLE BDC=70

THEREFORE ,

BD=BC..............(SIDES OPP. TO EQUAL ANGLES ARE EQUAL)

Step-by-step explanation: