Question

In the given figure, AB = AC. Prove that:
(i) DP = DQ
(ii) AP = AQ
(iii) AD bisects angle A
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Answer 1

Step-by-step explanation:

IF AB=AC

THEN ANGLE B=C

ANGLE C +115=180 (LINEAR PAIR)

C=180-115

= 65

SO B= C

SO B=65

SO A+B+C=180 (ASP)

65+65+A=180

A =50

Answer 2

Step-by-step explanation:

Given , AB=AC

DP is perpendicular to AB

And DQ is perpendicular to

angle BPD =angle DQC =90

BD=BC

PB = QC

so,triangle ABD is similar ti triangle DQC

Hence , DP=DQ

AP=AQ

Angle PAD =Angle DAQ

So AD BISECTS ANGLE A

HENCE PROVED

THANK YOU :)