In the given figure AB and AC and D is the midpiont of BC
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Full Question In the above figure, AB=AC and D is the mid-point of BC
Prove that (i) Is △ADB≅△ADC? (Give reason)
(ii) Is ∠B=∠C? Why?
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Step-by-step explanation:
AB=AC
P is mid point
BD=DC→(i)
in ΔABD b& ΔACD
AB=AC(given)
BD=DC fromeq(i)
AD=ADcommon
fromSSSrule
ΔADB≅ΔADC
∠B=∠C(CPCT)
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