Question

In the given figure AB and AC are opposite rays. find y=25l
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Answer 1

Step-by-step explanation:

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Answer 2

Answer:

$\huge\fbox \red{A}\fbox \green{n}\fbox \purple{s}\fbox \orange{w}\fbox \red{e}\fbox \color{aqua}{r}$

$\huge \bold{ \mathtt{ \underline{ \underline{ \color{red}{given \ratio}}}}}$

$\bold{ \angle \: cad = (5y + 21) \degree} \\ \bold{\angle \: bad = 2x \degree}$

$\huge \bold{ \mathtt{ \underline{ \underline{ \color{red}{to \: find \ratio}}}}}$

$\bold{value \: of \: x} \\ \bold{y = 251}$

$\huge \bold{ \mathtt{ \underline{ \underline{ \color{red}{solution \ratio}}}}}$

$\bold{ \angle \: cad + \angle \: bad = 180 \degree \: \: \: \: \: \: \: \: \: \: \: \: (leniar \: pair)} \\ \bold{i.e. \: (5y + 21) + 2x = 180 \degree}$

$\bold{\Rightarrow \: 5y + 21 + 2x = 180 \degree} \\ \bold{\Rightarrow \: 5 \times 251 + 2x = 180 - 21 = 159 \degree} \\ \bold{\Rightarrow \: x = \frac{159}{251 \times 5 \times 2}} \\ \bold{\Rightarrow \: x = \frac{159}{251 \times 10} = \frac{159}{2510} } \\ \bold{\Rightarrow \: 0.0633466135458} \\ \bold{0.06(approx)}$