Question

In the given figure AB and AC are the tangents to the circle with centre

‘O ‘ such that ∠ = 40

. Calculate ∠c​

Answer 1

Answer:

Tangent is perpendicular to radius at point of contact.

So, ∠ABO=∠ACO=90

∘

In a quadrilateral, the sum of the angles is 360

∘

.

∠BAC+∠BOC+∠ABO+∠ACO=360

∘

∴∠BAC+∠BOC=180

∘

∠BOC=180

∘

−40

∘

∠BOC=140

∘

So, option C is the answer