in the given figure, AB and BC are two chords of the circle with Centre O, where_BAO = 50°. ZBCO 35,
then_AOC is equal to
8
A
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Answered by
0
Answer:
∠AOC+BOD=2∠ABC+2∠BCD
=2∠ABC+∠BCD
=2∠BPD......
( since, angle formed on major arc is half of the angle formed on center)
∴∠AOC+∠BOD=2∠BPD
2∠BPD=50
o
+40
o
∠BPD=
2
90
o
=45
o
Answered by
1
Explanation:
I think 85 is the answer
I am not sure
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