In the given figure, AB and CD are two chords of a circle with centre O at distances of 6 cm and 8 cm respectively from O. If the radius of the circle is 10 cm, find the lengths of the chords.
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Join OB & OC ,
In triangle POB, (6)^2 + (PB)^2 = (10)^2
PB^2 =100-36
PB = 8 cm
length of chord AB= 2×8=16cm
In triangle COQ,
(8)^2 + (CQ)^2 = (10)^2
(CQ)^2 = 100 - 64
CQ = 6cm
length of chord CD = 2×6= 12cm
In triangle POB, (6)^2 + (PB)^2 = (10)^2
PB^2 =100-36
PB = 8 cm
length of chord AB= 2×8=16cm
In triangle COQ,
(8)^2 + (CQ)^2 = (10)^2
(CQ)^2 = 100 - 64
CQ = 6cm
length of chord CD = 2×6= 12cm
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