Question

In the given figure, AB and CD are two common tangents of the two circles. Show that AB = CD.​

Answer 1

Answer:

Let P be the point of intersection of AB and CD.

We know that length of two tangents drawn from an external point to a circle are equal.

⇒ AP=CP ---- ( 1 )

⇒ BP=DP ---- ( 2 )

Subtracting ( 2 ) from ( 1 ),

⇒ AP−BP=CP−DP

⇒ AB=CD

Thus, AB and CD are common tangents to two circles of unequal

radii then AB is not equal to CD.

Step-by-step explanation:

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