Question

in the given figure , AB and CD are two intersecting chords of circle . if CAB=40° and BCD =80° then angle CBD =?​

Answer 1

We have:

∠CDB = ∠CAB = 40° (Angles in the same segment of a circle)

In Δ CBD, we have:∠CDB + ∠BCD +∠CBD = 180° (Angle sum property of a triangle)

⇒ 40° + 80° + ∠CBD = 180°

⇒ ∠CBD = (180° - 120°) = 60°