In the given figure, AB and CD are two parallel chords of a circle with centre O and radius
13 cm such that AB = 24 cm and CD = 10 cm. If OP ⊥AB and OQ ⊥CD, determine the
length PQ. (Please give me a step by step answer. Not just the result )
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Answer:
7 cm
Explanation:
Given OP⊥AB and OQ⊥CD
CQ = QD = 3 cm
AP = BP = 4cm
In △OPA
OP^2 = OA^2-AP^2 = R^2 - 4^2
= 25-16
= 9
In △OCQ
OQ^2 = √r^2-3^2
= 4
PQ=OP+OQ
= 4+3
= 7 CM
therefore, 7cm is your right answer
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