Math, asked by as0141743, 27 days ago

in the given figure AB and CD bisect each other at K. Prove that AC=BD​

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Answers

Answered by ayureshpany2005
2

Step-by-step explanation:

K divides the whole figure in 2 triangles one is ∆AKC and ∆DKB

According to question

In ∆AKC and ∆DBK

angle AKC= angle BKC (vertically opposite angle)

Dk=kC( as k bisects cd)

AK=BK(as k bisects Ab)

As per SAS(side angle side) congruent rule both the triangles are congruent..

So AC=BD(CPCT)

{CPCT IS CALLED AS CORRESPONDING PART OF CONGRUENT TRIANGLE}

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