in the given figure AB and CD bisect each other at K. Prove that AC=BD
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Step-by-step explanation:
K divides the whole figure in 2 triangles one is ∆AKC and ∆DKB
According to question
In ∆AKC and ∆DBK
angle AKC= angle BKC (vertically opposite angle)
Dk=kC( as k bisects cd)
AK=BK(as k bisects Ab)
As per SAS(side angle side) congruent rule both the triangles are congruent..
So AC=BD(CPCT)
{CPCT IS CALLED AS CORRESPONDING PART OF CONGRUENT TRIANGLE}
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