In the given figure, AB are CD are two straight lines intersecting at M. If Angle CMB = 102° , then find all the other angles.
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Angle CMB = 102° , BMD = 78°, AMD = 102° and AMC = 78°.
Step-by-step explanation:
Given,
Angle CMB = 102°
so,
Angle AMD = 102° ( by Vertically opposite Angle as Angle AMD is vertically opposite to Angle CMB)
now,
consider AB as a line.
as sum of all angles on a straight line is 180°.
so,
Angle AMD + Angle DMB = 180°
102° + Angle DMB = 180°
Angle DMB = 180° - 102°
Angle DMB = 78°
now,
Angle AMC = 78° ( by vertically opposite angle ans Angle AMC is vertically opposite to Angle DMB )
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