Question

In the given figure, AB = (BC/2) , where BC = 14 cm (Use π = 22/7 ). Find :
(i) Area of quad. AEFD
(ii) Area of ∆ABC
(iii) Area of semicircle.
Hence find the area of shaded region.

Answer 1

Answer:

1. area of quad. AEFD is = 196
2. 14cm^2
3. 77cm^2

Answer 2

(i) Area of quad. AEFD = 196 cm²

(ii) Area of ∆ABC = 49 cm²

(iii) Area of semicircle = 77 cm²

The area of ∆ABC = 1/2 × AB × BC

( Using the formula area = 1/2 base × height )

AB = BC /2 = 7cm

=> 1/2 × 7 × 14

=> 49 cm²

The quadrilateral AEFD is a square as all the sides are equal i.e, equal to 14 cm -

The area of AEFD = 14 × 14

=> 196 cm²

The semicircle has a diameter BC = 14 cm and radius = 7 cm.

Area of the semicircle = π radius²/2

=> 22/7 × 49/2

=> 77 cm²