In the given figure, AB = BC and AC = CD. Prove that BAD : ADB = 3 : 1.
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Step-by-step explanation:
Let ∠ADB=x
In △ACD,AC=CD
⇒∠CAD=∠CDA=x
and, ∠ACB=∠CAD+∠CDA=x+x=2x
⇒∠BAC=∠ACB=2x.(∵ In ABC,AB=BC)
∴∠BAD=∠BAC+∠CAD
=2x+x=3x
And,
∠ADB
∠BAD
=
x
3x
=
1
3
i.e., ∠BAD:∠ADB=3:1
{ HENCE PROVED }
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