In the given figure ,AB =BC and Angle ABD =angle CBD .prove that angle DAB =angle DCB
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Let's consider triangle ABO and triangle CBO
AB=AC(given)
angle ABO=angle CBO(given)
OB=OB(common side)
therefore, traingle ABO=triangle CBO(by SAS rule of congruency)
angle DAB = angle ECB(by CPCT)
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AB=AC(given)
angle ABO=angle CBO(given)
OB=OB(common side)
therefore, traingle ABO=triangle CBO(by SAS rule of congruency)
angle DAB = angle ECB(by CPCT)
MARK ME AS A BRAINLIEST
Answered by
3
Plz give the figure... otherwise I can't answer...
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