In the given figure, AB = BC and BO is the angular bisector of ∠CBA, then prove
that AO=CO
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In ΔAOB and ΔBOC
OB=OB [common side]
AB=BC [given]
∠AOB=∠COB [because BO is the angular bisector and AB=BC]
⇒ ΔAOB ≅ ΔBOC
∴ OA = CO
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