In the given figure, AB=BC and LABO = LCBO,
then prove that LDAB - LECB...
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Step-by-step explanation:
In triangle AOB and triangle BOC
AB = BC ......(given)
OB = OB ......(common)
LABO = LCBO....(given)
triangle BAO congruent to triangle BCO (SAS)
LBAO = LBCO .....CPCT
Multiply by (-1) on both sides
- LBAO = - LBCO
Adding 180 on both sides
180 - LBAO = 180 - LBCO
LBAD = - LBCE.........(using linear pairs)
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