Question

in the given figure ,AB=BC and <ABD=<CBD.Prove that <DAB=<DCB​

Answer 1

In ΔABD and ΔCBD;

∠ABD=∠CBD   (Given)

BD=BD   (Common)

AB=CB   (Given)

By SAS rule, ΔABD≅ΔCBD.

Hence by CPCT,

∠DAB=∠DCB.

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Answer 2

In ΔABD and ΔCBD;

∠ABD=∠CBD   (Given)

BD=BD   (Common)

AB=CB   (Given)

By SAS rule, ΔABD≅ΔCBD.

Hence by CPCT,

∠DAB=∠DCB.

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Thank u.