Question

in the given figure AB || CD and AB =CD and triangle AOB congruent DOC .Prove that AO =AD and BC = 20 C​

Answer 1

$\huge \underbrace \mathfrak \red{Answer}$

AB∥CD         ( given )

In △AOB and △DOC,

∠AOB=∠DOC           (Vertically opposite angles)

∠OAB=∠ODC           (Alternate angles)

∠ABO=∠DCO           (Alternate angles)

From AAA (angle-angle-angle) similarity theorem,

△AOB∼△DOC

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