Question

In the given figure,AB=CD and AD=BC.Show that ∆ABC ≈∆CDA .Also show that <DAC=<BCA.​

Answer 1

Step-by-step explanation:

in ∆ ABC and ∆BAC

AB=CD (given)

AD=BC (given)

AC =AC (common)

by SSS rule

∆ABC≈∆ CDA

and,

<DAC=BCA (by CPCT rule)

Answer 2

Step-by-step explanation:

AB=CB(given)

AD =BC (given)

AC=AC(common)

Hence, triangle ABC=ACD by (s.s.s. Criteria)

Then by cpct. - <DAC=<BCA