Question

In the given figure AB=CD and AD=CB. Prove that Δ ABC ≅ ΔADC.​

Answer 1

${ \huge{ \pink{ \underline{ \underline{ \red{ \mathbb{ \bigstar{ \blue{answer}}}}}}}}} \\ \circ \sf \: to \: prove = > \angle \: adb = \angle \: cdb \\ \bf \: proof \: = > \: in \: \green \triangle \: adb \: and \pink \triangle \: cdb : \\ ad = cb(given) \\ ab = cb(given) \\ bd = bd(common) \\ \red \therefore \green \triangle \sf \: adb = \pink \triangle \: cdb \: by \: \green \: sss \: congruence \: rule$