Question

in the given figure AB||CD and angle AOC=x° if angle OAB=104° and angle OCD=116° find the value.​

Answer 1

Given :- in the given figure AB||CD and angle AOC= x° if angle OAB=104° and angle OCD=116° find the value of x° ?

Solution :-

construction :- Draw a line EF passing with O which is parallel to AB and CD .

now,

→ ∠OAB = 104°

and,

→ AB || EF

also,

→ AO is a transversal .

then,

→ ∠OAB + ∠AOF = 180°

→ ∠AOF = 180° - 104° = 76°

Similarly,

→ ∠OCD = 116°

and,

→ CD || EF

also,

→ CO is a transversal .

then,

→ ∠OCD + ∠COF = 180°

→ ∠COF = 180° - 116° = 64°

therefore,

→ x° = ∠AOF + ∠COF

→ x° = 76° + 64°

→ x° = 140° (Ans.)

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3.

In the fig, AB || CD,FIND x.(Hint:Prove that AOB-COD).

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Answer 2

Answer:

Given :- in the given figure AB||CD and angle AOC= x° if angle OAB=104° and angle OCD=116° find the value of x° ?

Solution :-

construction :- Draw a line EF passing with O which is parallel to AB and CD .

now,

→ ∠OAB = 104°

and,

→ AB || EF

also,

→ AO is a transversal .

then,

→ ∠OAB + ∠AOF = 180°

→ ∠AOF = 180° - 104° = 76°

Similarly,

→ ∠OCD = 116°

and,

→ CD || EF

also,

→ CO is a transversal .

then,

→ ∠OCD + ∠COF = 180°

→ ∠COF = 180° - 116° = 64°

therefore,

→ x° = ∠AOF + ∠COF

→ x° = 76° + 64°

→ x° = 140° (Ans.)