In the given figure, AB || CD and angle APQ = 70° and angle PRD = 130” Find the value of z and y .
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AB || CD,
∠ APQ = 50°
∠PRD = 130°
in figure QP joins AB at P
and if we extend it
vertically opposite angles are equal
∠PRD is intersect CD line
Angle BPR +angle PRD = 50+130=180
so , it is a property of parallel and trsnsversal line property
thats why ,theQPR is straight line
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