in the given figure, ab//cd and ef perpendicular ab . if eg is the transversal such that angle GED = 130° , find angle EGF.
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We know that AB || CD and GE is the transversal From the figure we know that ∠EGF and ∠GED are interior angles So we get ∠EGF + ∠GED = 180o By substituting the values ∠EGF + 130o = 180o On further calculation ∠EGF = 180o – 130o By subtraction ∠EGF = 50o Therefore, ∠EGF = 50oRead more on Sarthaks.com - https://www.sarthaks.com/717528/in-the-given-figure-ab-cd-and-ef-ab-if-eg-is-the-transversal-such-that-ged-130-find-egf
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