In the given figure AB||CD and O is the mid point of AD. Show that O is the mid point of BC.
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Step-by-step explanation:
In the given figure,
CD || AB
thus,
< CDA = < BAD
and,
< COD = < BOA (Vertically Opposite Angles)
Given, AO = OD,
thus by ASA (Angle-Side-Angle) Congruency Theorem,
∆AOB is congruent to ∆COD,
By C.P.C.T,
CO = OB,
thus O is the mid point of BC.
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