Question

In the given figure, AB || CD and transversal CE intersects AB

and CD respectively at points B and C. BF || CH such that A

FBC = HCD = 30", then value of ABEis
(A) 120 (C) 150 F

(B) 30° (D) 60°​

Answer 1

Answer:

120

Step-by-step explanation:

fbc + abf + abe = 180

abe = 180- 30 - 30 = 120

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Answer 2

$\huge\underline\mathcal\blue{ANSWER:-}$

120