In the given figure, AB || CD and XY is a transversal line intersects AB and CD at E and G respectively. If EF and GF are the bisectors of ∠BEG and ∠DGE respectively, then the measure of ∠EFG is equal to
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let bef= a
as AB //CD
SoDfe = 180 - a
EG is bisector of BEF
So FEG = a / 2 ,
And FG is bisector of DFE
So GFE=180-a)/2=90-a/2
In FGE
FGE= 180 - FEG - GFE
= 180-a/290 + a/2
= 90
Step-by-step explanation:
hope it helps you
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